Integrand size = 28, antiderivative size = 157 \[ \int \frac {(d \tan (e+f x))^{3/2}}{(a+i a \tan (e+f x))^3} \, dx=\frac {\sqrt [4]{-1} d^{3/2} \arctan \left (\frac {(-1)^{3/4} \sqrt {d \tan (e+f x)}}{\sqrt {d}}\right )}{8 a^3 f}-\frac {d \sqrt {d \tan (e+f x)}}{6 f (a+i a \tan (e+f x))^3}+\frac {d \sqrt {d \tan (e+f x)}}{6 a f (a+i a \tan (e+f x))^2}+\frac {d \sqrt {d \tan (e+f x)}}{8 f \left (a^3+i a^3 \tan (e+f x)\right )} \]
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Time = 0.40 (sec) , antiderivative size = 157, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {3639, 3677, 12, 16, 3630, 3614, 211} \[ \int \frac {(d \tan (e+f x))^{3/2}}{(a+i a \tan (e+f x))^3} \, dx=\frac {\sqrt [4]{-1} d^{3/2} \arctan \left (\frac {(-1)^{3/4} \sqrt {d \tan (e+f x)}}{\sqrt {d}}\right )}{8 a^3 f}+\frac {d \sqrt {d \tan (e+f x)}}{8 f \left (a^3+i a^3 \tan (e+f x)\right )}+\frac {d \sqrt {d \tan (e+f x)}}{6 a f (a+i a \tan (e+f x))^2}-\frac {d \sqrt {d \tan (e+f x)}}{6 f (a+i a \tan (e+f x))^3} \]
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Rule 12
Rule 16
Rule 211
Rule 3614
Rule 3630
Rule 3639
Rule 3677
Rubi steps \begin{align*} \text {integral}& = -\frac {d \sqrt {d \tan (e+f x)}}{6 f (a+i a \tan (e+f x))^3}-\frac {\int \frac {-\frac {a d^2}{2}+\frac {7}{2} i a d^2 \tan (e+f x)}{\sqrt {d \tan (e+f x)} (a+i a \tan (e+f x))^2} \, dx}{6 a^2} \\ & = -\frac {d \sqrt {d \tan (e+f x)}}{6 f (a+i a \tan (e+f x))^3}+\frac {d \sqrt {d \tan (e+f x)}}{6 a f (a+i a \tan (e+f x))^2}-\frac {\int \frac {6 i a^2 d^3 \tan (e+f x)}{\sqrt {d \tan (e+f x)} (a+i a \tan (e+f x))} \, dx}{24 a^4 d} \\ & = -\frac {d \sqrt {d \tan (e+f x)}}{6 f (a+i a \tan (e+f x))^3}+\frac {d \sqrt {d \tan (e+f x)}}{6 a f (a+i a \tan (e+f x))^2}-\frac {\left (i d^2\right ) \int \frac {\tan (e+f x)}{\sqrt {d \tan (e+f x)} (a+i a \tan (e+f x))} \, dx}{4 a^2} \\ & = -\frac {d \sqrt {d \tan (e+f x)}}{6 f (a+i a \tan (e+f x))^3}+\frac {d \sqrt {d \tan (e+f x)}}{6 a f (a+i a \tan (e+f x))^2}-\frac {(i d) \int \frac {\sqrt {d \tan (e+f x)}}{a+i a \tan (e+f x)} \, dx}{4 a^2} \\ & = -\frac {d \sqrt {d \tan (e+f x)}}{6 f (a+i a \tan (e+f x))^3}+\frac {d \sqrt {d \tan (e+f x)}}{6 a f (a+i a \tan (e+f x))^2}+\frac {d \sqrt {d \tan (e+f x)}}{8 f \left (a^3+i a^3 \tan (e+f x)\right )}+\frac {i \int \frac {\frac {1}{2} i a d^2-\frac {1}{2} a d^2 \tan (e+f x)}{\sqrt {d \tan (e+f x)}} \, dx}{8 a^4} \\ & = -\frac {d \sqrt {d \tan (e+f x)}}{6 f (a+i a \tan (e+f x))^3}+\frac {d \sqrt {d \tan (e+f x)}}{6 a f (a+i a \tan (e+f x))^2}+\frac {d \sqrt {d \tan (e+f x)}}{8 f \left (a^3+i a^3 \tan (e+f x)\right )}-\frac {\left (i d^4\right ) \text {Subst}\left (\int \frac {1}{\frac {1}{2} i a d^3+\frac {1}{2} a d^2 x^2} \, dx,x,\sqrt {d \tan (e+f x)}\right )}{16 a^2 f} \\ & = \frac {\sqrt [4]{-1} d^{3/2} \arctan \left (\frac {(-1)^{3/4} \sqrt {d \tan (e+f x)}}{\sqrt {d}}\right )}{8 a^3 f}-\frac {d \sqrt {d \tan (e+f x)}}{6 f (a+i a \tan (e+f x))^3}+\frac {d \sqrt {d \tan (e+f x)}}{6 a f (a+i a \tan (e+f x))^2}+\frac {d \sqrt {d \tan (e+f x)}}{8 f \left (a^3+i a^3 \tan (e+f x)\right )} \\ \end{align*}
Time = 1.84 (sec) , antiderivative size = 141, normalized size of antiderivative = 0.90 \[ \int \frac {(d \tan (e+f x))^{3/2}}{(a+i a \tan (e+f x))^3} \, dx=\frac {\left (\frac {1}{48}+\frac {i}{48}\right ) d \sec ^2(e+f x) \left (-3 \sqrt {2} \sqrt {d} \text {arctanh}\left (\frac {(1+i) \sqrt {d \tan (e+f x)}}{\sqrt {2} \sqrt {d}}\right ) \sec (e+f x) (\cos (3 (e+f x))+i \sin (3 (e+f x)))+(1+i) (3 \cos (2 (e+f x))+5 i \sin (2 (e+f x))) \sqrt {d \tan (e+f x)}\right )}{a^3 f (-i+\tan (e+f x))^3} \]
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Time = 0.68 (sec) , antiderivative size = 103, normalized size of antiderivative = 0.66
method | result | size |
derivativedivides | \(\frac {2 d^{4} \left (-\frac {i \arctan \left (\frac {\sqrt {d \tan \left (f x +e \right )}}{\sqrt {i d}}\right )}{16 d^{2} \sqrt {i d}}+\frac {-\left (d \tan \left (f x +e \right )\right )^{\frac {5}{2}}+\frac {10 i d \left (d \tan \left (f x +e \right )\right )^{\frac {3}{2}}}{3}+d^{2} \sqrt {d \tan \left (f x +e \right )}}{16 d^{2} \left (i d \tan \left (f x +e \right )+d \right )^{3}}\right )}{f \,a^{3}}\) | \(103\) |
default | \(\frac {2 d^{4} \left (-\frac {i \arctan \left (\frac {\sqrt {d \tan \left (f x +e \right )}}{\sqrt {i d}}\right )}{16 d^{2} \sqrt {i d}}+\frac {-\left (d \tan \left (f x +e \right )\right )^{\frac {5}{2}}+\frac {10 i d \left (d \tan \left (f x +e \right )\right )^{\frac {3}{2}}}{3}+d^{2} \sqrt {d \tan \left (f x +e \right )}}{16 d^{2} \left (i d \tan \left (f x +e \right )+d \right )^{3}}\right )}{f \,a^{3}}\) | \(103\) |
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 341 vs. \(2 (127) = 254\).
Time = 0.25 (sec) , antiderivative size = 341, normalized size of antiderivative = 2.17 \[ \int \frac {(d \tan (e+f x))^{3/2}}{(a+i a \tan (e+f x))^3} \, dx=\frac {{\left (12 \, a^{3} f \sqrt {-\frac {i \, d^{3}}{64 \, a^{6} f^{2}}} e^{\left (6 i \, f x + 6 i \, e\right )} \log \left (-\frac {2 \, {\left (i \, d^{2} e^{\left (2 i \, f x + 2 i \, e\right )} + 8 \, {\left (a^{3} f e^{\left (2 i \, f x + 2 i \, e\right )} + a^{3} f\right )} \sqrt {\frac {-i \, d e^{\left (2 i \, f x + 2 i \, e\right )} + i \, d}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}} \sqrt {-\frac {i \, d^{3}}{64 \, a^{6} f^{2}}}\right )} e^{\left (-2 i \, f x - 2 i \, e\right )}}{d}\right ) - 12 \, a^{3} f \sqrt {-\frac {i \, d^{3}}{64 \, a^{6} f^{2}}} e^{\left (6 i \, f x + 6 i \, e\right )} \log \left (-\frac {2 \, {\left (i \, d^{2} e^{\left (2 i \, f x + 2 i \, e\right )} - 8 \, {\left (a^{3} f e^{\left (2 i \, f x + 2 i \, e\right )} + a^{3} f\right )} \sqrt {\frac {-i \, d e^{\left (2 i \, f x + 2 i \, e\right )} + i \, d}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}} \sqrt {-\frac {i \, d^{3}}{64 \, a^{6} f^{2}}}\right )} e^{\left (-2 i \, f x - 2 i \, e\right )}}{d}\right ) + {\left (4 \, d e^{\left (6 i \, f x + 6 i \, e\right )} + 4 \, d e^{\left (4 i \, f x + 4 i \, e\right )} - d e^{\left (2 i \, f x + 2 i \, e\right )} - d\right )} \sqrt {\frac {-i \, d e^{\left (2 i \, f x + 2 i \, e\right )} + i \, d}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}}\right )} e^{\left (-6 i \, f x - 6 i \, e\right )}}{48 \, a^{3} f} \]
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\[ \int \frac {(d \tan (e+f x))^{3/2}}{(a+i a \tan (e+f x))^3} \, dx=\frac {i \int \frac {\left (d \tan {\left (e + f x \right )}\right )^{\frac {3}{2}}}{\tan ^{3}{\left (e + f x \right )} - 3 i \tan ^{2}{\left (e + f x \right )} - 3 \tan {\left (e + f x \right )} + i}\, dx}{a^{3}} \]
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Exception generated. \[ \int \frac {(d \tan (e+f x))^{3/2}}{(a+i a \tan (e+f x))^3} \, dx=\text {Exception raised: RuntimeError} \]
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none
Time = 0.83 (sec) , antiderivative size = 158, normalized size of antiderivative = 1.01 \[ \int \frac {(d \tan (e+f x))^{3/2}}{(a+i a \tan (e+f x))^3} \, dx=-\frac {1}{24} \, d^{4} {\left (\frac {3 i \, \sqrt {2} \arctan \left (\frac {8 \, \sqrt {d^{2}} \sqrt {d \tan \left (f x + e\right )}}{4 i \, \sqrt {2} d^{\frac {3}{2}} + 4 \, \sqrt {2} \sqrt {d^{2}} \sqrt {d}}\right )}{a^{3} d^{\frac {5}{2}} f {\left (\frac {i \, d}{\sqrt {d^{2}}} + 1\right )}} + \frac {3 i \, \sqrt {d \tan \left (f x + e\right )} d^{2} \tan \left (f x + e\right )^{2} + 10 \, \sqrt {d \tan \left (f x + e\right )} d^{2} \tan \left (f x + e\right ) - 3 i \, \sqrt {d \tan \left (f x + e\right )} d^{2}}{{\left (d \tan \left (f x + e\right ) - i \, d\right )}^{3} a^{3} d^{2} f}\right )} \]
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Time = 4.69 (sec) , antiderivative size = 155, normalized size of antiderivative = 0.99 \[ \int \frac {(d \tan (e+f x))^{3/2}}{(a+i a \tan (e+f x))^3} \, dx=\frac {\frac {5\,d^3\,{\left (d\,\mathrm {tan}\left (e+f\,x\right )\right )}^{3/2}}{12\,a^3\,f}-\frac {d^4\,\sqrt {d\,\mathrm {tan}\left (e+f\,x\right )}\,1{}\mathrm {i}}{8\,a^3\,f}+\frac {d^2\,{\left (d\,\mathrm {tan}\left (e+f\,x\right )\right )}^{5/2}\,1{}\mathrm {i}}{8\,a^3\,f}}{-d^3\,{\mathrm {tan}\left (e+f\,x\right )}^3+d^3\,{\mathrm {tan}\left (e+f\,x\right )}^2\,3{}\mathrm {i}+3\,d^3\,\mathrm {tan}\left (e+f\,x\right )-d^3\,1{}\mathrm {i}}-\frac {\sqrt {\frac {1}{256}{}\mathrm {i}}\,{\left (-d\right )}^{3/2}\,\mathrm {atan}\left (\frac {16\,\sqrt {\frac {1}{256}{}\mathrm {i}}\,\sqrt {d\,\mathrm {tan}\left (e+f\,x\right )}}{\sqrt {-d}}\right )\,2{}\mathrm {i}}{a^3\,f} \]
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